[egenix-users] comparing DateTime types

[Steve Holden]

----- Original Message -----
From: "Max M" <maxm at mxm.dk>
To: "egenix-users" <egenix-users at lists.egenix.com>
Sent: Thursday, February 21, 2002 12:15 PM
Subject: [egenix-users] comparing DateTime types


> Hi
>
> This works as I expect:
> type(mx.DateTime.now()) == type(mx.DateTime.DateTime(2002))
>  >>> 1
>
> But this doesn't:
> type(mx.DateTime.now()) == type(mx.DateTime.DateTimeType)
>  >>> 0
>
> Do I have to compare instances? I would have thought that comparing
with
> the "DateTimeType" directly would suffice.
>
>>> import mx.DateTime as dt
>>> dt.DateTimeType
<type 'DateTime'>
>>> type(dt.now())
<type 'DateTime'>

The magic you were looking for is probably

    type(mx.DateTime.now()) == mx.DateTime.DateTimeType

The problem here is that type(mx.DateTime.DateTimeType) is a type, whose
type should therefore be typeType.

>>> type(dt.DateTimeType)
<type 'type'>

Hope this helps.

regards
 Steve
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